PL/SQL sample queries Part - III

50.WAP to accept a string and print it in reverse order
DECLARE
STR VARCHAR2(100):='&sTR';
STR1 VARCHAR2(100);
N NUMBER(5);
L VARCHAR2(20);
BEGIN
N:=LENGTH(STR);
FOR I IN 1..N
LOOP
L:=SUBSTR(STR,I,1);
STR1:=L||STR1;
END LOOP;
DBMS_OUTPUT.PUT_LINE(STR1);
END;
/
51.Write a program to accept a number and find out the sum of first and
last digits
DECLARE
A NUMBER(4):=&A;
B NUMBER(5):=0;
C NUMBER(5):=0;
S NUMBER(5);
BEGIN
IF A>9 THEN
C:=SUBSTR(A,1,1);
B:=SUBSTR(A,LENGTH(A),1);
S:=B+C;
ELSE
S:=A;
END IF;
DBMS_OUTPUT.PUT_LINE('SUM OF FIRST AND LAST DIGIT IS '||S);
END;
/
52.WAP to accept the basic salary and find out the ta,da,hra,lic and gs
i)ta 20% of basic, da 10% of basic, hra 30% of basic, lic 5% of basic
DECLARE
BS NUMBER(6,2):=&BS;
TA NUMBER(6,2);
DA NUMBER(6,2);
HRA NUMBER(6,2);
GS NUMBER(6,2);
LIC NUMBER(6,2);
NS NUMBER(8,2);
BEGIN
TA:=BS*(20/100);
HRA:=BS*(30/100);
DA:=BS*(10/100);
LIC:=BS*(5/100);
GS:=TA+HRA+DA;
NS:=GS-LIC;
DBMS_OUTPUT.PUT_LINE('EMPLOYEE BS IS '||BS);
DBMS_OUTPUT.PUT_LINE('GROSS SALARY IS '||GS);
DBMS_OUTPUT.PUT_LINE('NET SALARY IS '||NS);
END;
/
53.WAP to accept the length and breadth of a rectangle and find out the perimeter
DECLARE
L NUMBER(4,2):=&L;
B NUMBER(4,2):=&B;
A NUMBER(4,2);
BEGIN
A:=2*(L+B);
DBMS_OUTPUT.PUT_LINE('THE PERIMETER OF RECTANGLE IS '||A);
END;
/
54.WAP to accept the cost price and selling price of an item and find
the loss or profit
DECLARE
CP NUMBER(25,2):=&CP;
SP NUMBER(25,2):=&SP;
AMT NUMBER(7,2);
BEGIN
IF CP < SP THEN
AMT:=SP-CP;
DBMS_OUTPUT.PUT_LINE('PROFIT IS '||AMT);
ELSE
AMT:=CP-SP;
DBMS_OUTPUT.PUT_LINE('LOSS IS '||AMT);
END IF;
END;
/
55.Writ a program to generate the following series
53 53 53 53 53
43 43 43 43
33 33 33
23 23
13
DECLARE
V VARCHAR2(20);
BEGIN
FOR I IN REVERSE 1..5
LOOP
FOR J IN 1..I
LOOP
V:=V||I||CHR(179);
END LOOP;
DBMS_OUTPUT.PUT_LINE(V);
V:=NULL;
END LOOP;
END;
/
56.WAP to accept a no in binary format and print it in decimal format
DECLARE
N VARCHAR2(20):=&N;
PRO NUMBER(10,4):=0;
L VARCHAR2(10);
BEGIN
FOR I IN 1..LENGTH(N)
LOOP
L:=SUBSTR(N,I,1);
PRO:=PRO+L*POWER(2,LENGTH(N)-I);
END LOOP;
DBMS_OUTPUT.PUT_LINE('THE DECIMAL NUMBER IS '||PRO);
END;
/
57.WAP to accept two nos and input and find one no is raised to another one (without using any function)
DECLARE
A NUMBER:=&A;
B NUMBER:=&B;
R NUMBER:=1;
BEGIN
FOR I IN 1..B
LOOP
R:=R*A;
END LOOP;
DBMS_OUTPUT.PUT_LINE('A RAISED POWER B IS '||R);
END;
/
58.WAP to accept a sentence and count the no of chars in that sentence
DECLARE
STR VARCHAR2(100):='&STR';
NO NUMBER(5):=0;
I NUMBER;
BEGIN
I:=INSTR(STR,'.');
DBMS_OUTPUT.PUT_LINE('NO OF CHAR IS '||I);
END;
/
59.WAP to accept two strings and display the large one among those
DECLARE
STR1 VARCHAR2(100):='&STR1';
STR2 VARCHAR2(100):='&STR2';
BEGIN
IF LENGTH(STR1) > LENGTH(STR2) THEN
DBMS_OUTPUT.PUT_LINE(STR1 ||' IS GREATER');
ELSIF LENGTH(STR1) < LENGTH(STR2) THEN
DBMS_OUTPUT.PUT_LINE(STR2 ||' IS GREATER');
ELSE
DBMS_OUTPUT.PUT_LINE('BOTH STRINGS ARE EQUAL');
END IF;
END;
/
60.WAP to display all the nos whose sum of digits is 9 from 1 to 9999
DECLARE
N NUMBER;
M NUMBER;
S NUMBER:=0;
BEGIN
FOR I IN 1..999
LOOP
N:=I;
WHILE N>0
LOOP
M:=MOD(N,10);
S:=S+M;
N:=TRUNC(N/10);
END LOOP;
IF S=9 THEN
DBMS_OUTPUT.PUT_LINE(I||' ');
END IF;
S:=0;
END LOOP;
END;
/
61.WAP to accept a no and find the sum in a single digit
DECLARE
N NUMBER(4):=&N;
S NUMBER(10):=0;
BEGIN
WHILE LENGTH(N)>1
LOOP
FOR I IN 1..LENGTH(N)
LOOP
S:=S+SUBSTR(N,I,1);
END LOOP;
N:=S;
S:=0;
END LOOP;
DBMS_OUTPUT.PUT_LINE('THE SUM IN SINGLE DIGIT IS '||N);
END;
/
62.Ente the no of days and find out the no of years and no of days and months
DECLARE
D NUMBER:=&D;
Y NUMBER;
M NUMBER;
BEGIN
Y:=TRUNC(D/365);
M:=TRUNC(MOD(D,365)/30);
D:=MOD(MOD(D,365),30);
DBMS_OUTPUT.PUT_LINE(Y||' YEARS '||M||' MONTHS '||D||' DAYS');
END;
/
63.WAP to accept the date and print all the weekdays along with the given date
DECLARE
D DATE:='&D';
V VARCHAR2(20);
BEGIN
FOR I IN 1..7
LOOP
V:=TO_CHAR(D,'DAY')||D;
DBMS_OUTPUT.PUT_LINE(V);
D:=D+1;
END LOOP;
END;
/
64.WAP while purchasing certain items,discount of each is as follows
i) If qty purchased > 1000 discount is 20%
ii) If the qty and price per item are i/p then calculate the expenditure
DECLARE
QTY NUMBER(5):=&QTY;
UP NUMBER(6,2):=&UP;
DIS NUMBER(6,2):=0;
TAMT NUMBER(10,2);
BILL NUMBER(10,2);
BEGIN
BILL:=QTY*UP;
IF BILL > 1000 THEN
DIS:=BILL*20/1000;
END IF;
TAMT:=BILL-DIS;
DBMS_OUTPUT.PUT_LINE('THE TOTAL AMOUNT IS '||TAMT);
END;
/
65.Write a program to accept a string and count the no of individual chars
DECLARE
V VARCHAR2(100):='&V';
V1 VARCHAR2(100);
LB NUMBER;
LA NUMBER;
DIFF NUMBER;
C CHAR;
N NUMBER(5):=0;
BEGIN
V1:=V;
WHILE LENGTH(V1)>0
LOOP
C:=SUBSTR(V1,1,1);
LB:=LENGTH(V1);
V1:=REPLACE(V1,C);
LA:=NVL(LENGTH(V1),0);
DIFF:=LB-LA;
IF ASCII(C)=32 THEN
DBMS_OUTPUT.PUT_LINE('SPACE'||' EXISTS '||DIFF||' TIMES');
ELSE
DBMS_OUTPUT.PUT_LINE(C||' EXISTS '||DIFF||' TIMES');
END IF;
N:=N+DIFF;
END LOOP;
DBMS_OUTPUT.PUT_LINE('TOTAL LENGTH OF THE GIVEN STRING '||V||'='||N);
END;
/
66.Write a program to display all combination of 1,2,&3
BEGIN
FOR I IN 1..3
LOOP
FOR J IN 1..3
LOOP
FOR K IN 1..3
LOOP
DBMS_OUTPUT.PUT_LINE(I||J||K);
END LOOP;
END LOOP;
END LOOP;
END;
/
67.Write a program to find out the series 12+22+32+42+....++n2
DECLARE
N NUMBER:=&N;
A NUMBER:=1;
B NUMBER:=2;
C NUMBER:=0;
D NUMBER:=0;
S NUMBER:=0;
BEGIN
WHILE A<=N
LOOP
C:=C+A*A;
A:=A+2;
END LOOP;
WHILE B<=N
LOOP
D:=D+B*B;
B:=B+2;
END LOOP;
S:=C-D;
DBMS_OUTPUT.PUT_LINE('RESULT IS '||S);
END;
/
68.Write a program to accep the time in HH & MIN format and find the total senconds
DECLARE
H NUMBER:=&HOUR;
M NUMBER:=&MINUTE;
S NUMBER(10):=0;
BEGIN
S:=(H*60*60)+(M*60);
DBMS_OUTPUT.PUT_LINE(H||' HOURS '||M||' MINUTES '||'IS'||S||' SECONDS');
END;
/
69.WAP to accept the distance between two cities in km and convert into mts ,cm & ft
DECLARE
D NUMBER:=&D;
M NUMBER:=0;
CM NUMBER:=0;
FT NUMBER:=0;
BEGIN
M:=D*1000;
CM:=M*100;
FT:=ROUND(CM/12.3);
DBMS_OUTPUT.PUT_LINE('DISTANCE IN METERS IS '||M);
DBMS_OUTPUT.PUT_LINE('DISTANCE IN CENTIMETERS IS '||CM);
DBMS_OUTPUT.PUT_LINE('DISTANCE IN FOOT IS '||FT);
END;
/
70.Write a program to find the series x+x2/2!+x3/3!+.....+xn/n!
DECLARE
N NUMBER:=&N;
X NUMBER:=&X;
S NUMBER:=0;
F NUMBER:=1;
BEGIN
FOR I IN 1..N
LOOP
FOR J IN 1..I
LOOP
F:=F*J;
END LOOP;
S:=ROUND(s+(POWER(X,I)/F),3);
F:=1;
END LOOP;
DBMS_OUTPUT.PUT_LINE('SUM OF NUMBER IS '||S);
END;
/
71.Write a program to accept the population of hyderabad each year the population increases
2% after 4y what is the population of hyd
DECLARE
P NUMBER:=&P;
L NUMBER;
BEGIN
FOR J IN 1..4
LOOP
L:=P*2/100;
P:=P+L;
END LOOP;
DBMS_OUTPUT.PUT_LINE('POPULATION OF HYDERABAD AFTER 4 YEARS IS '||TRUNC(P));
END;
/
72.WAP to accept the 3 dates and display the most recently month among 3 dates
DECLARE
D1 DATE:='&D1';
D2 DATE:='&D2';
D3 DATE:='&D3';
M1 NUMBER;
M2 NUMBER;
M3 NUMBER;
BEGIN
M1:=TO_CHAR(D1,'MM');
M2:=TO_CHAR(D2,'MM');
M3:=TO_CHAR(D3,'MM');
IF M1>M2 AND M1>M3 THEN
DBMS_OUTPUT.PUT_LINE(TO_CHAR(D1,'MON')||' IS RECENT MONTH');
ELSIF M2>M1 AND M2>M3 THEN
DBMS_OUTPUT.PUT_LINE(TO_CHAR(D2,'MON')||' IS RECENT MONTH');
ELSE
DBMS_OUTPUT.PUT_LINE(TO_CHAR(D3,'MON')||' IS RECENT MONTH');
END IF;
END;
/
73.Accept a string and print in the following format
O
OR
ORA
ORAC
ORACL
ORACLE
DECLARE
V VARCHAR2(20):='&V';
C VARCHAR(20);
BEGIN
FOR I IN 1..LENGTH(V)
LOOP
C:=SUBSTR(V,1,I);
DBMS_OUTPUT.PUT_LINE(C);
END LOOP;
END;
/
74.Write a program to accept the annual income of the emp and find the income tax
i) If the annsal > 60000 then tax is 10% of income
ii) If the annsal > 100000 then tax is Rs 800+16% of income
iii) If the annsal > 140000 then tax is Rs 2500+25% of income
DECLARE
AI NUMBER(10,2):=&ANNUALINCOME;
TAX NUMBER(10,3):=0;
BEGIN
IF AI BETWEEN 36000 AND 50000 THEN
TAX:=AI*10/100;
ELSIF AI BETWEEN 50000 AND 100000 THEN
TAX:=800+AI*16/100;
ELSIF AI > 100000 THEN
TAX:=2500+AI*25/100;
END IF;
DBMS_OUTPUT.PUT_LINE('ANNUAL INCOME '||AI);
DBMS_OUTPUT.PUT_LINE('TAX '||TAX);
END;
/